If the average of $p$ numbers is $q^2$ and that of $q$ numbers is $p^2$, then the average of $(p+q)$ numbers is:
Answer & explanation
Correct answer: option 3
average of p numbers = q2
Sum of p numbers = pq2
average of q numbers = p2
Sum of q numbers = qp2
average of p+q numbers = (Sum of p+q numbers)/(p+q) = (pq2+qp2)/(p+q) = pq(p+q)/(p+q) = pq
The correct answer is Option (3) → $pq$