A first order reaction is found to have a rate constant, \(k = 5.5 × 10^{-14}s^{-1}\). Find the half life of the reaction.

\(t_{1/2}  = 1.26 ×  10^{13} s\)

The correct answer is option 4. \(t_{1/2}  = 1.26 ×  10^{13} s\).

Given,

Rate constant, \(k = 5.5 × 10^{-14}s^{-1}\)

We know, for a first order reaction half life,

\(t_{1/2} = \frac{0.693}{k}\)

\(t_{1/2} = \frac{0.693}{5.5 × 10^{-14}s^{-1}}\)

\(t_{1/2} = 1.26 × 10^{13}s\)