A first order reaction is found to have a rate constant, \(k = 5.5 × 10^{-14}s^{-1}\). Find the half life of the reaction.
Answer & explanation
Correct answer: option 4
The correct answer is option 4. \(t_{1/2} = 1.26 × 10^{13} s\).
Given,
Rate constant, \(k = 5.5 × 10^{-14}s^{-1}\)
We know, for a first order reaction half life,
\(t_{1/2} = \frac{0.693}{k}\)
\(t_{1/2} = \frac{0.693}{5.5 × 10^{-14}s^{-1}}\)
\(t_{1/2} = 1.26 × 10^{13}s\)