If the salary of A is 12% more than that of B, then by what percentage is the salary of B less than that of A? [Give your answer correct to 1 place of decimal.]

10.7%

If the salary of A is 12% more than that of B

Let the salary of B = 100

according to the question,

Then the salary of the A = 112

Salary of B = (112-100) × \(\frac{100}{112}\) = 10.71% less than A.