A father's age is one year more than 6 times of his son's age. After 2 years, the father's age would be 1 years less than five times the son's age. Find the present age of the father.
Answer & explanation
Correct answer: option 2
At present :
⇒ F = 6S + 1 ..................(i)
After 2 years:
⇒ F + 2 = 5(S + 2) - 1
⇒ F + 2= 5S + 10 - 1
⇒ F = 5S + 7
⇒ 6S + 1 = 5S + 7 ( from (i) )
⇒ S = 6
⇒ Therefore, age of Father = 6S + 1 = (6 × 6) + 1 = 37 years