The feasible region corresponding to the linear constraints of a Linear Programming Problem (LPP) is represented by the shaded region in the given figure. Which of the following is not a constraint to the given LPP?

Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(x-y \ge 1\)
Every point of the feasible region satisfies every constraint. The shaded region is bounded by the y-axis and the lines \(x + 2y = 10\), \(x + y = 2\) and \(x - y = 1\). The point (1, 3) lies inside it. At (1, 3):
\(x + 2y = 7\), so \(x + 2y \le 10\) holds.
\(x + y = 4\), so \(x + y \ge 2\) holds.
\(x - y = -2\), so \(x - y \le 1\) holds and \(x - y \ge 1\) fails.
So the region lies on the side \(x - y \le 1\) of the line \(x - y = 1\), and \(x - y \ge 1\) is not a constraint of this LPP.