Match List - I with List - II.
|
List – I |
List – II |
|
(A) $14-\frac{x-1}{10}=\frac{x+5}{6}-3$ |
(I) 4 |
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(B) $(x-5)^2-(x+3)^2=48$ |
(II) $-\frac{23}{2}$ |
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(C) $6(x-4)=4(x-3)-(3x-8)$ |
(III) 61 |
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(D) $(2x-1) (2x+3)=(2x-7) (2x+7)$ |
(IV) -2 |
Choose the most appropriate answer from the options given below:
Answer & explanation
Correct answer: option 3
14− (x−1)/10=(x+5)/6 − 3
⇒ (x+5)/6 + (x−1)/10 = 17
⇒ 10x + 50 + 6x - 6 = 17*60 ⇒ 16x = 1020 - 44 ⇒ x = 61
(x−5)2−(x+3)2=48
⇒ x2+25-10x-x2-9-6x = 48
⇒ 16-16x = 48 ⇒ 16x = -32 ⇒ x = -2
6(x−4)=4(x−3)−(3x−8)
⇒ 6x-24 = 4x-12-3x+8
⇒ 6x-4x+3x = 24-12+8
⇒ 5x = 20 ⇒ x = 4
(2x−1)(2x+3)=(2x−7)(2x+7)
⇒ 4x2+6x-2x-3 = 4x2-14x+14x-49
⇒ 4x-3 = -49 ⇒ x = -46/4 = -23/2
The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)