Match List - I with List - II. List – I List – II (A) $14-\frac{x-1}{10}=\frac{x+5}{6}-3$ (I) 4 (B) $(x-5)^2-(x+3)^2=48$ (II) $-\frac{23}{2}$ (C) $6(x-4)=4(x-3)-(3x-8)$ (III) 61 (D) $(2x-1) (2x+3)=(2x-7) (2x+7)$ (IV) -2 Choose the most appropriate answer from the options given below:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)