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The maximum value of $Z=5x+3y $ subject to the constraints $2x+4y≤16, 3x+y ≤9, x, y ≥0$ is : |
12 25 19 15 |
19 |
The correct answer is Option (3) → 19
$3x+y=9$ ...(1) $2x+4y=16$ ...(2) $\text{4×Eq. (1)-Eq. (2)}$, we get $10x=20$ $x=2⇒y=3$ Objective, $Z=5x+3y$ $Z(0,0)=0$ $Z(0,4)=12$ $Z(3,0)=15$ $Z(2,3)=5×2+3×3=19$ → maximum value |
