CUET Preparation Today
What is the force between two small charged spheres having charges of $4 \times 10^{-7} C$ and $6 \times 10^{-7} C$ placed 60 cm apart in air? |
$3 \times 10^{-3} N$ $4 \times 10^{-3} N$ $6 \times 10^{-3} N$ $9 \times 10^{-3} N$ |
$6 \times 10^{-3} N$ |
The correct answer is Option (3) → $6 \times 10^{-3} N$ According to Coloumb's law - $F=K\frac{|q_1q_2|}{r^2}$ $=8.99×10^9×\frac{4×10^{-7}×6×10^{-7}}{(0.6)^2}$ $≃6 \times 10^{-3} N$ |
