What is the force between two small charged spheres having charges of $4 \times 10^{-7} C$ and $6 \times 10^{-7} C$ placed 60 cm apart in air?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $6 \times 10^{-3} N$
According to Coloumb's law -
$F=K\frac{|q_1q_2|}{r^2}$
$=8.99×10^9×\frac{4×10^{-7}×6×10^{-7}}{(0.6)^2}$
$≃6 \times 10^{-3} N$