Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: P Block Elements

Question:

Greenish-Yellow colour gas, \(X\)with pungent smell and suffocating odour is produced when \(KMnO_4\) reacts with \(HCl\). \(X\)on reaction with excess \(NH_3\) forms \(Y\) and \(Z\). \(X\) on reaction with \(I_2\) in water forms \(HCl\) and an oxoacid of iodine, \(W\). Identify \(X, Y, Z, W\).

  \(X\) \(Y\) \(Z\) \(W\)
(1) \(Cl_2\) \(N_2\) \(NH_4Cl\) \(HIO_3\)
(2) \(F_2\) \(N_2\) \(NH_4F\) \(HIO_4\)
(3) \(Cl_2\) \(NCl_3\) \(HCl\) \(HIO_3\)
(4) \(Cl_2\) \(NCl_3\) \(N_2\) \(HIO_3\)

 

Options:

1

2

3

4

Correct Answer:

1

Explanation:

The correct answer is option 1. 1.

Let us explain each part of the information provided along with the associated reactions:

1. Greenish-yellow gas (\(X\)) produced when \(KMnO_4\) reacts with \(HCl\):

When potassium permanganate (\(KMnO_4\)) reacts with hydrochloric acid (\(HCl\)), chlorine gas (\(Cl_2\)) is produced along with other products according to the following reaction:

\[2KMnO_4 + 16HCl \rightarrow 2KCl + 2MnCl_2 + 8H_2O + 5Cl_2\]

2. Reaction of \(X\) with excess \(NH_3\) to form \(Y\) and \(Z\):

Chlorine gas (\(Cl_2\)) reacts with excess ammonia (\(NH_3\)) to form nitrogen gas (\(N_2\)) and ammonium chloride (\(NH_4Cl\)). The reaction proceeds as follows:

\[8NH_3 + 3Cl_2 \rightarrow 6NH_4Cl + N_2\]

3. Reaction of \(X\) with \(I_2\) in water to form \(W\) and \(HCl\):

Chlorine gas (\(Cl_2\)) reacts with iodine (\(I_2\)) in water to form hydrochloric acid (\(HCl\)) and nitric acid (\(HNO_3\)). The reaction can be represented as:

\[I_2 + 2Cl_2 + 6H_2O \rightarrow 2HCl + 2HIO_3 + 4HCl + 2HClO\]

Simplifying, we get:

\[I_2 + 5Cl_2 + 6H_2O \rightarrow 5HCl + 2HIO_3\]

Therefore, the overall reactions associated with the formation of \(Y\), \(Z\), and \(W\) are:

1. \(X\) (\(Cl_2\)) reacts with \(NH_3\) to form \(Y\) (\(N_2\)) and \(Z\) (\(NH_4Cl\)).

2. \(X\) (\(Cl_2\)) reacts with \(I_2\) in water to form \(W\) (\(HNO_3\)) and \(HCl\).