A is a point outside of a circle with centre O. AP and AQ are two tangents of the circle. If AP = a2 + 14 and AQ = 239, then what is the value of a?
Answer & explanation
Correct answer: option 3
Concept Used
Tangents drawn from an external point to a circle are equal
Solution
= AP = AQ
= \( { a}^{2 } \) + 14 = 239
= \( { a}^{2 } \) = 225
= a = 15
Therefor, the answer is 15.