If cos θ = 4x/(1+4x^2), then what is the value of sin θ ?

cosθ = \(\frac{4x}{1 + 4x²}\)

{ cosθ = \(\frac{B}{H}\) }

Using pythagoras theorem,

P² + B² = H²

P² + (4x)² = (1+4x²)²

P² = 1 + 16x4 + 8x² - 16x² = ( 1 - 4x² )²

P = 1 - 4x² 

Now,

sinθ

= \(\frac{P}{H}\)

= \(\frac{ 1 - 4x² }{1+4x²}\)