'A' spins a spinner that is split into 10 equal sections marked as 1, 3, 2, 1, 2, 2, 3, 1, 2, 1. What is the probability that the spinner will land on number 2?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(\frac{2}{5}\)
The 10 sections are equal, so each is equally likely, and the probability is favourable sections ÷ total sections.
Sections marked 2 in 1, 3, 2, 1, 2, 2, 3, 1, 2, 1: the 3rd, 5th, 6th and 9th, that is, 4 sections
Probability \(=\frac{4}{10}=\frac{2}{5}\)