CUET Preparation Today
'A' spins a spinner that is split into 10 equal sections marked as 1, 3, 2, 1, 2, 2, 3, 1, 2, 1. What is the probability that the spinner will land on number 2? |
$\frac{1}{10}$ $\frac{2}{5}$ $\frac{1}{2}$ $\frac{1}{5}$ |
$\frac{2}{5}$ |
The number of sections labelled '2' = 4 Total number of sections = 10 P(number 2) = 4/ 0 = 2/5 |
