The straight line $\frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}$ is
Answer & explanation
Correct answer: option 4
Equations of x, y and z-axis are
$\frac{x}{1}=\frac{y}{0} =\frac{z}{0}, \frac{x}{0}=\frac{y}{1} =\frac{z}{0}$ and $ \frac{x}{0}=\frac{y}{0} =\frac{z}{1}$ respectively.
The given line is $\frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}$
We observe that $3× 0 + 1×0 + 0 × 1 = 0. $
Hence, the line is perpendicular to z-axis.