A sum of money becomes ₹20070 after 3 year and ₹30105 after 6 years on compound interest. The sum will be |
13380 8920 5292 25560 |
13380 |
The correct answer is Option (1) → 13380 We are given:
The compound interest formula: $A = P(1 + r)^t$ Step 1: Express $A_6$ in terms of $A_3$ $A_6 = A_3 \cdot (1 + r)^3$ $30105 = 20070 \cdot (1 + r)^3$ $(1 + r)^3 = \frac{30105}{20070} \approx 1.5$ $1 + r = \sqrt[3]{1.5} \approx 1.1447$ Step 2: Find the principal P $A_3 = P (1 + r)^3 ⇒20070 = P \cdot 1.1447^3$ But $1.1447^3 \approx 1.5$, so: $20070 = P \cdot 1.5 ⇒P = \frac{20070}{1.5} \approx 13380$ |