ABCD is a cyclic quadrilateral in which AB = 15 cm, BC = 12 cm and CD = 10 cm. If AC bisects BD, then what is the measure of AD?
Answer & explanation
Correct answer: option 3
If ABCD is a cyclic quadrilateral in which AC bisects BD.
\(\frac{AD}{BC}\) = \(\frac{AB}{DC}\)
\(\frac{AD}{12}\) = \(\frac{15}{10}\)
AD = \(\frac{3}{2}\) x 12 = 18 cm.