ABCD is a cyclic quadrilateral in which AB = 15 cm, BC = 12 cm and CD = 10 cm. If AC bisects BD, then what is the measure of AD?

15 cm 13.5 cm 18 cm 20 cm

18 cm

If ABCD is a cyclic quadrilateral in which AC bisects BD. \(\frac{AD}{BC}\) = \(\frac{AB}{DC}\) \(\frac{AD}{12}\) = \(\frac{15}{10}\) AD = \(\frac{3}{2}\) x 12 = 18 cm.