Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

What is the ratio of the third proportional of 5 & 9 and the mean proportional between 1.6 and 8.1?

Options:

2:9

9:5

9:2

9:11

Correct Answer:

9:2

Explanation:

Third proportional a, b, c

                            c = \(\frac{b2}{a}\)

third proportional = 5, 9, x

                             x = \(\frac{81}{5}\)

 

Mean proportional = \(\sqrt {1.6 × 8.1}\)

                           = 3.6

3rd proportional  :     mean proportional

                       \(\frac{81}{5}\) : 3.6

                         9 : 2