Electric field intensity at a point varies as $\frac{1}{r^3}$ due to:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → a short electric dipole
$E_{axial}=\frac{1}{4πε_0}.\frac{2Pr^3}{r^3}$
$E_{equitorial}=\frac{1}{4πε_0}.\frac{Pr^3}{r^3}$
∴ Electric field intensity at a point varies as $\frac{1}{r^3}$ due to a short electric dipole.