Match List-I with List-II
|
List-I Common name |
List-II IUPAC name |
|
(A) Oxalic acid |
(I) Ethanedioic acid |
|
(B) Adipic acid |
(II) Alpha hydroxy propanoic acid |
|
(C) Lactic acid |
(III) Hexanedioic acid |
|
(D) Phthalic acid |
(IV) Benzene-1,2-dicarboxylic acid |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
Common names of carboxylic acids come from their sources; IUPAC names count the carbon atoms of the chain. A dicarboxylic acid takes the ending -dioic acid on the name of the alkane containing both carboxyl carbons, and an aromatic acid is named from benzene with the positions of the –COOH groups.
(A) Oxalic acid — This matches (I) Ethanedioic acid. It is \( \ce{HOOC-COOH} \), two carboxyl carbons joined together: a two-carbon dioic acid.
(B) Adipic acid — This matches (III) Hexanedioic acid. It is \( \ce{HOOC-(CH2)4-COOH} \), with six carbon atoms counting both carboxyl carbons; it is used to make nylon-6,6.
(C) Lactic acid — This matches (II) Alpha hydroxy propanoic acid. It is \( \ce{CH3-CH(OH)-COOH} \), propanoic acid with an –OH group on the carbon next to –COOH (the α-carbon, C-2), that is, 2-hydroxypropanoic acid; it is formed when milk turns sour.
(D) Phthalic acid — This matches (IV) Benzene-1,2-dicarboxylic acid. It is \( \ce{C6H4(COOH)2} \) with the two –COOH groups on neighbouring (ortho) ring carbons.
Shortcut: (B)-(III) appears only in Option (2).