Practicing Success
What is the value of the following expression? $2^2(\frac{x^a}{x^b})^{(a+b)}×3^2(\frac{x^b}{x^c})^{(b+c)}×6^{-2}(\frac{x^c}{x^a})^{(a+c)}$ |
1 0 4 9 |
1 |
$2^2(\frac{x^a}{x^b})^{(a+b)}×3^2(\frac{x^b}{x^c})^{(b+c)}×6^{-2}(\frac{x^c}{x^a})^{(a+c)}$ Put the value of every variable as 1. = $2^2(\frac{1^1}{1^1})^{(1+1)}×3^2(\frac{1^1}{1^1})^{(1+1)}×6^{-2}(\frac{1^1}{1^1})^{(1+1)}$ = 4 × 9 ÷ 36 = 36 ÷ 36 = 1 |