What is the value of the following expression?
$2^2(\frac{x^a}{x^b})^{(a+b)}×3^2(\frac{x^b}{x^c})^{(b+c)}×6^{-2}(\frac{x^c}{x^a})^{(a+c)}$
Answer & explanation
Correct answer: option 1
$2^2(\frac{x^a}{x^b})^{(a+b)}×3^2(\frac{x^b}{x^c})^{(b+c)}×6^{-2}(\frac{x^c}{x^a})^{(a+c)}$
Put the value of every variable as 1.
= $2^2(\frac{1^1}{1^1})^{(1+1)}×3^2(\frac{1^1}{1^1})^{(1+1)}×6^{-2}(\frac{1^1}{1^1})^{(1+1)}$
= 4 × 9 ÷ 36
= 36 ÷ 36 = 1