Find the odd one out in the given series.
3, 12, 27, 48, 76, 108
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 76
The terms are 3 times the squares of 1, 2, 3, 4, 5 and 6.
\(3\times1^2=3\), \(3\times2^2=12\), \(3\times3^2=27\), \(3\times4^2=48\)
The fifth term should be \(3\times5^2=75\), but 76 is given
\(3\times6^2=108\) fits again
Every term but one follows the rule, so 76 is the odd one out.