Let A, B, C be three sets such that $A∪B∪C=U$, where U is the universal set. Then, $\{(A-B)∪(B-C)∪(C-A)\}'$ is equal to |
$A∪B∪C$ $A∪(B∩C)$ $A∩B∩C$ $A∩(B∪C)$ |
$A∩B∩C$ |
The correct answer is Option (3) → $A∩B∩C$ We have, $\{(A-B)∪(B-C)∪(C-A)\}'$ $=(A-B)'∩(B-C)'∩(C-A)'$ $=A∩B∩C$ [See Venn-Diagram] |