A resistor of resistance R, an inductor of (20/π) H and a capacitor of (5/π) μF are connected in series to a voltage source of 220 V, 50 Hz. The value of current in the circuit is 4 A. The impedance of the circuit is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 55 Ω
Given:
Voltage $V = 220 \,\text{V}$
Frequency $f = 50 \,\text{Hz}$
Inductance $L = \frac{20}{\pi} \,\text{H}$
Capacitance $C = \frac{5}{\pi} \,\mu\text{F} = \frac{5}{\pi} \times 10^{-6} \,\text{F}$
Current $I = 4 \,\text{A}$
Impedance of circuit:
$Z = \frac{V}{I} = \frac{220}{4} = 55 \,\Omega$
Final Answer: $55 \,\Omega$