A resistor of resistance R, an inductor of (20/π) H and a capacitor of (5/π) μF are connected in series to a voltage source of 220 V, 50 Hz. The value of current in the circuit is 4 A. The impedance of the circuit is |
40 Ω 20 Ω 45 Ω 55 Ω |
55 Ω |
The correct answer is Option (4) → 55 Ω Given: Voltage $V = 220 \,\text{V}$ Frequency $f = 50 \,\text{Hz}$ Inductance $L = \frac{20}{\pi} \,\text{H}$ Capacitance $C = \frac{5}{\pi} \,\mu\text{F} = \frac{5}{\pi} \times 10^{-6} \,\text{F}$ Current $I = 4 \,\text{A}$ Impedance of circuit: $Z = \frac{V}{I} = \frac{220}{4} = 55 \,\Omega$ Final Answer: $55 \,\Omega$ |