A rectangular paper of width 8cm and length 22cm rolled along it width and a cylinder is formed.

On the above Intimation, Solve the question given below

If the outer surface area of cylinder is pointed @ ₹0.5/cm², then the total cost of painting is

₹88

The correct answer is Option 1: 88

Step 1: Identify cylinder dimensions

Rolling along width means:

Height = 8 cm
Circumference = 22 cm

So,

2πr = 22

Using π = 22/7

r = 22 / (2 × 22/7) = 3.5 cm

Step 2: Outer surface area of cylinder

Outer surface area (curved surface area) = 2πrh

= 2 × (22/7) × 3.5 × 8

= 2 × (22/7) × (7/2) × 8

= 176 cm²

Step 3: Cost of painting

Rate = ₹0.5 per cm²

Cost = 176 × 0.5

Cost = ₹88