The velocity of a particle v at an instant t is given by v = at +$bt^2$ the dimension of b is
Answer & explanation
Correct answer: option 4
According to principle of dimensional Analysis Dimension of terms on LHS and RHS must be equal.
Hence dimension of $at ,bt^2$ is same as that of v.
⇒ $[bt^2]$ = $[LT^{-1}]$
⇒ [b] = $[LT^{-3}]$