A 60 μF capacitor is connected t

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Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

A 60 μF capacitor is connected to a 110 V, 60 Hz AC supply. What is the root mean square value of current in the circuit?

Options:

1.49A

2.19A

2.49A

Correct Answer:

2.49A

Explanation:

Impedence X_c = 1/2πfC

= 1/(2x3.14x60x10x10^-6 )

= 44.2Ω

So, I_rms = $\frac{V_{rms}}{X_C}$= 110/44.2 = 2.49 A