CUET Preparation Today
A 60 μF capacitor is connected to a 110 V, 60 Hz AC supply. What is the root mean square value of current in the circuit? |
1.49A 2.19A 2.49A 3A |
2.49A |
The correct answer is Option 3:2.49A
The opposition offered by the capacitor to the AC flow is given by: $X_C = \frac{1}{2\pi fC}$
$X_C = \frac{1}{2 \times 3.141 \times 60 \times 60 \times 10^{-6}}$
$X_C = \frac{10^6}{22619.4} \approx 44.21\ \Omega$
Using Ohm's law for AC circuits: $I_{rms} = \frac{V_{rms}}{X_C}$
$I_{rms} = \frac{110\ \text{V}}{44.21\ \Omega}$
$I_{rms} \approx 2.488\ \text{A}$
≈2.49 A
|
