If cosec θ=13/12, then the value of (2sinθ-3cosθ)/(4sinθ-9cosθ) is:

cosecθ = \(\frac{13 }{12}\)

P² +  B² = H²

(12)² + B² = (13)²

B = 5

Now ,

\(\frac{2sinθ - 3cosθ }{ 4sinθ - 9cosθ}\)

= \(\frac{2×12 - 3×5 }{ 4×12 - 9×5}\)

=  \(\frac{24 - 15 }{3}\)

= 3