If $u=3x^{12}$ and $v=x^6$, then $\frac{

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

If $u=3x^{12}$ and $v=x^6$, then $\frac{du}{dv}$ is:

Options:

$6x^6$

$36x^{11}$

$6x^5$

$3x^6$

Correct Answer:

$6x^6$

Explanation:

$u=3x^{12},\,v=x^6⇒u=3v^2⇒\frac{du}{dv}=6v=6x^6$