Ethyl bromide is converted to succinic acid by using the following reagents in steps:-
A. KCN
B. Br2
C. KOH(alc.)
D. H2O/H
Choose the correct sequence of conversion-
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → C, B, A and D.
Ethyl bromide to succinic acid
Step 1: Treatment with KOH (alc.) (C)
Ethyl bromide \((C_2H_5Br)\) reacts with alcoholic potassium hydroxide \((KOH(alc.))\) via elimination reaction (\(E_2\) mechanism) to form ethene \((C_2H_4)\).

Step 2: Bromination with \(Br_2\) (B)
Ethene undergoes bromination with bromine \((Br_2)\) to form 1,2-dibromoethane.

Step 3: Treatment with KCN (A)
1,2-Dibromoethane reacts with potassium cyanide \((KCN)\) in a nucleophilic substitution reaction, replacing both bromine atoms with cyanide groups, forming 1,2-dicyanoethane.

Step 4: Hydrolysis with \(H_2O/H^+\) (D)
1,2-Dicyanoethane undergoes acidic hydrolysis in the presence of water and acid \((H_2O/H^+)\) to form succinic acid.

Conclusion:
The correct sequence is C → B → A → D.
Hence, the correct answer is:
**Option 1: C, B, A, and D.**