ABCD is a cyclic quadrilateral with AB as a diameter of the circle. If ∠ADC = 118°, then the measure (in degrees) of ∠BAC is :
Answer & explanation
Correct answer: option 4
As , ABCD is a cyclic quadrilateral . So, Sum of opposite angles is 180º.
∠ABC + ∠ADC = 180º
∠ABC + 118º = 180º
∠ABC = 62º
We know that , Diameter of circle for 90º angle on circumference.
In triangle ABC
∠A +∠B + ∠C = 180º
∠A + 62º + 90º = 180º
∠A = 28º
So, ∠BAC = 28º