ABCD is a cyclic quadrilateral with AB as a diameter of the circle. If ∠ADC = 118°, then the measure (in degrees) of ∠BAC is :

28

As , ABCD is a cyclic quadrilateral . So, Sum of opposite angles is 180º.

∠ABC + ∠ADC = 180º

∠ABC + 118º = 180º

∠ABC = 62º

We know that , Diameter of circle for 90º angle on circumference.

In triangle ABC

∠A +∠B + ∠C = 180º

∠A + 62º + 90º = 180º

∠A = 28º

So, ∠BAC = 28º