Practicing Success
Practicing Success
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If $\left|\begin{array}{lll}x+1 & x+2 & x+a \\ x+2 & x+3 & x+b \\ x+3 & x+4 & x+c\end{array}\right|=0$, then a, b, c are in |
A.P G.P H.P none of these |
A.P |
Apply R1 → R1 + R3 – 2R2 $\left|\begin{array}{ccc}0 & 0 & a+c-2 b \\ x+2 & x+3 & x+b \\ x+3 & x+4 & x+c\end{array}\right|=0$ ⇒ a + c –2b = 0 ⇒ a, b, c are in A.P Hence (1) is the correct answer. |
