What is the potential difference at the centre C ?
Answer & explanation
Correct answer: option 1
We know that potential is a scalar quantity
$V=\frac{1}{4 \pi \varepsilon_0} \frac{q}{r}$
Where r is the distance between charge and point where potential has to be found.
∴ total potential at center C
$=\frac{1}{4 \pi \varepsilon_0}\left(q_1+q_2+q_3+q_4\right) . \frac{1}{r}$
$=\frac{1}{4 \pi \varepsilon_0 r}(+q-q+q-q)$
= 0