If tan A = 3, then what is the value of 3 sin A cos A ?

We are given that :-

tanA = 3

tanA = \(\frac{3}{1}\)

{ we know, tan x = \(\frac{P}{B}\) }

By using pythagoras theorem,

P² + B² = H²

3² + 1² = H²

H = √10

Now,

3 sin A cos A

= 3 × \(\frac{3}{√10 }\) × \(\frac{1}{√10 }\)

=  \(\frac{9}{10 }\)