If tan A = 3, then what is the value of 3 sin A cos A ? |
8/9 9/10 7/9 9/11 |
9/10 |
We are given that :- tanA = 3 tanA = \(\frac{3}{1}\) { we know, tan x = \(\frac{P}{B}\) } By using pythagoras theorem, P² + B² = H² 3² + 1² = H² H = √10 Now, 3 sin A cos A = 3 × \(\frac{3}{√10 }\) × \(\frac{1}{√10 }\) = \(\frac{9}{10 }\) |