If tan A = 3, then what is the value of 3 sin A cos A ?

8/9 9/10 7/9 9/11

9/10

We are given that :- tanA = 3 tanA = \(\frac{3}{1}\) { we know, tan x = \(\frac{P}{B}\) } By using pythagoras theorem, P² + B² = H² 3² + 1² = H² H = √10 Now, 3 sin A cos A = 3 × \(\frac{3}{√10 }\) × \(\frac{1}{√10 }\) =  \(\frac{9}{10 }\)