Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

A charge +10 μC is placed at (0 mm, 0 mm) Another charge –5 μC is moved from (3 mm, 0 mm) to (0 mm, 3 mm). Work done by the external agency is

Options:

0 J

-150 J

+150 J

-300 J

Correct Answer:

0 J

Explanation:

Here, A and B are equidistant from Origin ,OA = OB

∴ VA = VB

Than ΔV = VA – VB = 0

Hence, W = q(Δv) = 0