What is the product formed when benzyl ethyl ether reacts with HI?

Benzyl iodide and ethyl alcohol.

The correct answer is Option (4) → Benzyl iodide and ethyl alcohol.

Benzyl ethyl ether is $C_6H_5CH_2–O–C_2H_5$.

Reaction with HI cleaves the C–O bond, giving:

$C_6H_5CH_2–I+C_2H_5OH$

• The benzyl group forms benzyl iodide
• The ethyl group becomes ethyl alcohol

Correct answer: Benzyl iodide and ethyl alcohol