What is the product formed when benzyl ethyl ether reacts with HI?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Benzyl iodide and ethyl alcohol.
Benzyl ethyl ether is $C_6H_5CH_2–O–C_2H_5$.
Reaction with HI cleaves the C–O bond, giving:
$C_6H_5CH_2–I+C_2H_5OH$
- The benzyl group forms benzyl iodide
- The ethyl group becomes ethyl alcohol
Correct answer: Benzyl iodide and ethyl alcohol