A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is (g = 10 m/s²) nearly : 

4.2 kg m/s

Impulse = linear change in momentum = p_f - p_i

v = \(\sqrt{2 g H}\)

g = 10 m/s² ; H = 10 m

v = 10\(\sqrt{2}\)

p_i = mv(j) = 2 x 0.15 x 10\(\sqrt{2}\) (j)  ; p_f = mv(-j) = 2 x 0.15 x 10\(\sqrt{2}\) (-j) 

Impulse : I = 4.2 kg m/s