A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is (g = 10 m/s2) nearly :
Answer & explanation
Correct answer: option 1
Impulse = linear change in momentum = pf - pi
v = \(\sqrt{2 g H}\)
g = 10 m/s2 ; H = 10 m
v = 10\(\sqrt{2}\)
pi = mv(j) = 2 x 0.15 x 10\(\sqrt{2}\) (j) ; pf = mv(-j) = 2 x 0.15 x 10\(\sqrt{2}\) (-j)
Impulse : I = 4.2 kg m/s