If the hypotenuse of an isosceles right-angled triangle is 10 cm, then the other two sides (in cm) are __________. |
10√2 and 10√2 8√2 and 8√2 6√2 and 6√2 5√2 and 5√2 |
5√2 and 5√2 |
As 2 sides is equal in isosceles triangle Therefore, AB = AC Using pythagoras theorem, = \( {BC }^{2 } \) = \( {AB }^{2 } \) + \( {AC }^{2 } \) = \( {BC }^{2 } \) = 2\( {AB }^{2 } \) = \( {BC }^{2 } \)/2 = \( {AB }^{2 } \) = \( {AB }^{2 } \) = 50 = AB = 5\(\sqrt {2 }\) Therefore, AB and AC are 5\(\sqrt {2 }\). |