India plays two matches each with the West Indies and Australia. In any match, the probabilities of India getting 0,1 and 2 points are 0.45, 0.05 and 0.50, respectively. Assuming that the outcomes are independent, the probability of India getting at least 7 points, is |
$\frac{1}{80}$ $\frac{7}{80}$ $\frac{7}{8}$ $\frac{1}{8}$ |
$\frac{7}{80}$ |
Since there are four matches to be played. So, India can get a maximum of 8 points. ∴ P(India gets atleast 7 points) = P(Getting exactly 7 points) + P (Getting exactly 8 points) = P(Getting 2 points in each of the three matches and 1 in one match) + P(Getting 2 points in each of the four matches) $={^4C}_3 (0.5)^3 (0.05)^1+ {^4C}_4 (0.5)^4$ $= 4 × (0.5)^3 × (0.05) + (0.5)^4 = (0.5)^3 (0.2 +0.5)=\frac{7}{80}$ |