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The magnetic induction along the axis of an air cored solenoid is 0.03 T. On placing an iron core inside the solenoid the magnetic induction becomes 1.5 T. The relative permeability of iron core will be |
12 40 50 300 |
50 |
$B_{iron} = \mu B_{air}$ $\Rightarrow \mu = \frac{B_{iron}}{B_{air}}=\frac{1.5}{0.03} = 50$ |
