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For which value of k, the given system of linear equations is inconsistent ? $3x+6y + 3z = 4 $ $x+ ky + 2z= 6 $ $z= 7 $ |
k= -2 k = 0 k = 2 k = 1 |
k = 2 |
The correct answer is Option (3) → $k = 2$ For inconsistent $|A|=\begin{vmatrix}3&6&3\\1&k&2\end{vmatrix}=0$ $⇒3k-6=0⇒k=2$ |
