CUET Preparation Today
Four charges q, -q, 2Q and Q are placed at the corners of a square ABCD of side '2a' as shown. The field at the midpoint CD is zero. Find the ratio of $\frac{q}{Q}$.
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$2\sqrt{5}$ $\frac{2\sqrt{2}}{5}$ $\frac{5\sqrt{5}}{2}$ $5\sqrt{2}$ |
$\frac{5\sqrt{5}}{2}$ |
The correct answer is Option (3) → $\frac{5\sqrt{5}}{2}$ |
