Find the HCF of reciprocal of \(\frac{3}{4}\), \(\frac{9}{10}\), \(\frac{15}{16}\)?

\(\frac{2}{45}\)

Reciprocal of Numbers are = \(\frac{4}{3}\), \(\frac{10}{9}\), \(\frac{16}{15}\)

Required number = \(\frac{HCF\;of\;Numerator}{LCM\;of\;Denominator}\)

                          =  \(\frac{HCF\;of\;4, 10,16}{LCM\;of\;3, 9, 15}\) = \(\frac{2}{45}\)