If $(1 + cot^2 θ) + ( 1 + (cot^2 θ)^{-1})$ is equal to k, then $\sqrt{k}$ = ?
Answer & explanation
Correct answer: option 3
( 1 + cot²θ ) + {1 + (cot²θ)-1}\) = k
( 1 + cot²θ ) + ( 1 + tan²θ ) = k
{ we know, cosec²θ - cot²θ = 1 & sec²θ - tan²θ = 1
}
cosec²θ + sec²θ = k
\(\frac{sin²θ + cos²θ }{ sin²θ.cos²θ }\) = k
{ sin²θ + cos²θ = 1 }
\(\frac{1 }{ sin²θ.cos²θ }\) = k
cosec²θ.sec²θ = k
\(\sqrt {k }\) = cosecθ.secθ