CUET Preparation Today
In a bag there are 15 red and 5 white balls. Two balls are drawn in succession, without replacement. The first drawn ball is found to be red. The probability that second ball is also red, is equal to |
$\frac{3}{10}$ $\frac{7}{10}$ $\frac{5}{19}$ $\frac{14}{19}$ |
$\frac{14}{19}$ |
Total number of ways of selecting the second ball $={ }^{19} C_1=19$. Total number of ways of selecting the second ball suitably $={ }^{14} C_1=14$. Thus, required probability $\frac{14}{19}$. |
