In a circle centred at O, AB is a chord and C is any point on AB, such that OC is perpendicular to AB. If the length of the chord is 16 cm and OC = 6 cm, the radius of circle is:

10 cm 8 cm 6 cm 12 cm

10 cm

We have, AB = 16 cm  then, AC = 8 cm OC = 6 cm In ΔAOC = OA2 = OC2 + AC2 = OA2 = 62 + 82  = OA2 = 36 + 64 = OA2 = 100 = OA = 10 cm