In a circle centred at O, AB is a chord and C is any point on AB, such that OC is perpendicular to AB. If the length of the chord is 16 cm and OC = 6 cm, the radius of circle is:
Answer & explanation
Correct answer: option 1
We have,
AB = 16 cm
then, AC = 8 cm
OC = 6 cm
In ΔAOC
= OA2 = OC2 + AC2
= OA2 = 62 + 82
= OA2 = 36 + 64
= OA2 = 100
= OA = 10 cm