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If $A=\begin{bmatrix}2&4\\x&\frac{-1}{2}\end{bmatrix}$ and A is singular, then x is equal to: |
$\frac{1}{4}$ $-\frac{1}{4}$ -7 32 |
$-\frac{1}{4}$ |
The correct answer is Option (2) → $-\frac{1}{4}$ $A=\begin{bmatrix}2&4\\x&\frac{-1}{2}\end{bmatrix}$ A is singular, $|A|=0$ $⇒-1-4x=0$ $⇒x=-\frac{1}{4}$ |
