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In $\triangle ABC, \angle A = 54^\circ$. If I is the incenter of the triangle, then the measure of $\angle BIC$ is: |
68° 54° 148° 117° |
117° |
\(\angle\)BIC = 90 + \(\angle\)A/2 = \(\angle\)BIC = 90 + \(\frac{54}{2}\) Therefore, \(\angle\)BIC = \({117}^\circ\). |
