In $\triangle ABC, \angle A = 54^\circ$. If I is the incenter of the triangle, then the measure of $\angle BIC$ is:
Answer & explanation
Correct answer: option 4
\(\angle\)BIC = 90 + \(\angle\)A/2
= \(\angle\)BIC = 90 + \(\frac{54}{2}\)
Therefore, \(\angle\)BIC = \({117}^\circ\).