A hot wire voltmeter measures the voltages across the inductor, the capacitor and the resistor as 150 V, 100 V and 50 V across a series, LCR circuit. If resistance is $100 \Omega$, the current in the circuit is:

1.87 A

The correct answer is Option (3) → 1.87 A

$V_{L-C}=\sqrt{{V_L}^2+{V_C}^2}$

$=\sqrt{150^2+100^2}=\sqrt{32500}$

$≃180.08V$

and,

$I=\frac{V_{total}}{R}$ [By Ohm's law]

$=\frac{187.08}{100}≃1.87A$