CUET Preparation Today
If y = log (sin x), then $\frac{d^2 y}{d x^2}$ is : |
–cosec2x sec2x –cosec x cot x sec x tan x |
–cosec2x |
$y = \log (\sin x) \Rightarrow \frac{d y}{d x}=\frac{\cos x}{\sin x}=\cot x$ $\Rightarrow \frac{d^2 y}{d x^2}=-cosec^2 x$ Hence (1) is correct answer. |
