If y = log (sin x), then $\frac{d^2 y}{d x^2}$ is :
Answer & explanation
Correct answer: option 1
$y = \log (\sin x) \Rightarrow \frac{d y}{d x}=\frac{\cos x}{\sin x}=\cot x$
$\Rightarrow \frac{d^2 y}{d x^2}=-cosec^2 x$
Hence (1) is correct answer.
If y = log (sin x), then $\frac{d^2 y}{d x^2}$ is :
Correct answer: option 1
$y = \log (\sin x) \Rightarrow \frac{d y}{d x}=\frac{\cos x}{\sin x}=\cot x$
$\Rightarrow \frac{d^2 y}{d x^2}=-cosec^2 x$
Hence (1) is correct answer.