CUET Preparation Today
If A and B are non-singular square matrices of the same order, then $(AB^{-1})^{-1}=$ |
$A^{-1}B$ $A^{-1}B^{-1}$ $BA^{-1}$ $AB$ |
$BA^{-1}$ |
The correct answer is Option (3) → $BA^{-1}$ $(AB^{-1})^{-1}=(B^{-1})^{-1}A^{-1}$ $=BA^{-1}$ |
