If A and B are non-singular square matrices of the same order, then $(AB^{-1})^{-1}=$
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $BA^{-1}$
$(AB^{-1})^{-1}=(B^{-1})^{-1}A^{-1}$
$=BA^{-1}$
If A and B are non-singular square matrices of the same order, then $(AB^{-1})^{-1}=$
Correct answer: option 3
The correct answer is Option (3) → $BA^{-1}$
$(AB^{-1})^{-1}=(B^{-1})^{-1}A^{-1}$
$=BA^{-1}$