The electric field intensity at the mid point of a dipole with charge ±q and dipole length 2a is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{4πε_0}\frac{2q}{a^2}$
Electric field due to dipole is -
$E=\frac{1}{4πε_0}\frac{2p}{r^3}$
Now, $\vec p=q.2a$ [p = dipole moment]
$∴E=\frac{1}{4πε_0}\frac{q.2a}{a^2}=\frac{1}{4πε_0}\frac{2q}{a}$